How do I convert a s-core into a percentile in SPSS?
The below computes 100 P(Z < z) in SPSS. So putting z equal to 1.96 gives a perc of 97.5% since 97.5 percent of the Normal distribution is less than the mean plus 2 standard deviations.
compute perc=100*CDF.NORMAL(z,0,1). exe.