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| Cortina and Dunlap(1997) give an example evaluating the detection rate of a test (positive/negative result) to detect schizophrenia (disorder). | Cortina and Dunlap (1997) give an example evaluating the detection rate of a test (positive/negative result) to detect schizophrenia (disorder). |
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| The base rate of schizophrenia in adults (2%) | |
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| This is a more intuitive way of illustrating the Bayesian equation: | The test will correctly identify schizophrenia (give a positive result) on 95% of people with schizophrenia The test will correctly identify normal individuals (give a negative result) on 97% of normal people. Despite this we can show the [attachment:baye.doc test is unreliable]. This is a more intuitive way of illustrating the equivalent Bayesian equation: |
How do I calculate and interpret conditional probabilities?
Gigerenzer (2002) suggests a way to obtain conditional probabilities using frequencies in a decision tree.
Cortina and Dunlap (1997) give an example evaluating the detection rate of a test (positive/negative result) to detect schizophrenia (disorder).
To do this one fixes the following:
The base rate of schizophrenia in adults (2%)
The test will correctly identify schizophrenia (give a positive result) on 95% of people with schizophrenia
The test will correctly identify normal individuals (give a negative result) on 97% of normal people.
Despite this we can show the [attachment:baye.doc test is unreliable].
This is a more intuitive way of illustrating the equivalent Bayesian equation:
P(No disorder|+ result) = $$\frac{\mbox{P(No disorder) * P(+ result | No disorder)}}{\mbox{P(No disorder) * P(+ result | No disorder) + P(Disorder) * P(- result | Disorder)}}$$
References
Cortina JM, Dunlap WP (1997) On the logic and purpose of significance testing Psychological methods 2(2) 161-172.
Gigerenzer G. (2002) Reckoning with risk: learning to live with uncertainty. London: Penguin.