How do I compute Cohen's d in SPSS?

Cohen's d represents the difference between a pair of group means expressed in terms of the average group standard deviation.

Cohen's d = $$\frac\mbox{difference in group means}}{\mbox{average group sd}} $$

This may be worked out using the routine of Smithson which is located in the demo file in the power talk at [:StatsCourse2009:Graduate Statistics Courses 2009.] Alternatively the average group sd is equal to the square root of the Mean Square Error outputted using the ONEWAY procedure in SPSS and dividing this into the difference in the two means which can be obtained using the means procedure. For example for comparing the two age 'pr' group means we can run the below

ONEWAY
  age BY pr
  /MISSING ANALYSIS.
MEANS
  TABLES=age  BY pr
  /CELLS MEAN COUNT STDDEV  .